Set 1 = {A, B}
Set 2 = {A, C}
All, let me try to explain the problem of excluding certain code points from different sets when doing the analysis.
Let’s assume two scenarios for the hypothetical analysis:
Scenario 1:
Set 1 = {A, B}
Set 2 = {A, C}
For Set 1, it was concluded A is a variant of B.
In Set 2, it was concluded A is not a variant of C.
Then, the only resulting variant set is A à B (symmetry implied)
Scenario 2:
Set 1 = {A, B}
Set 3 = {A, B, C}
For Set 1, A is deemed variant of B
In Set 3, A is deemed variant of B, B deemed a variant of C, but A not a variant of C.
The resulting variant sets are A à B, Bà C; and due to transitivity AàC is also a variant pair.
My point was that by excluding a code point from the analysis can result in different result as to the variant sets identified.
Hope this helps clarify.
Dennis